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Separate part variation from measurement variation

Select representative parts, appraisers and conditions.. Follow the visual, practise a decision, then check your thinking.

Fictional teaching examples and AI-generated illustrations. Proposed changes and goals are not achieved results. Use the written instructions and check local conditions before applying a method.

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Teaching view 1 of 2

Separate part variation from measurement variation

Measurement-component comparison uses supplied repeatability SD 0.003 mm and reproducibility SD 0.004 mm, combining in quadrature to gauge SD 0.005 mm. Against total SD 0.025 mm, the gauge is 20% of standard deviation but 4% of variance. The two percentages use different denominators and are not acceptance thresholds.
Original OPEX teaching diagram. Follow the steps below, then try the practice question. View full size ↗

A measurement study separates variation due to the measurement system from variation between parts. Select parts and conditions that represent the intended use, and use a design appropriate to whether repeated measurements are possible. Randomized, blinded repeats reduce memory and order effects. Repeatability and reproducibility are distinct components; estimated independent variances combine before taking a square root. Consequently, a percentage based on standard deviations is not the same as a percentage of variance. Do not treat a sample design or a generic percentage as a universal acceptance criterion. Interpret the result against the measurement decision, risk, resolution and other relevant sources of measurement error.

Follow the method

  1. Supplied standard deviations (mm)
  2. Standard deviation (mm)
  3. Measurement component
  4. Repeatability
  5. Reproducibility
  6. Combined gauge
  7. Total study
  8. Study variation ratio / % of total SD
  9. Variance contribution / % of total variance

Read the example carefully

10parts×3operators×2repeats=60 illustrative readings.

sqrt(0.003²+0.004²)=0.005 mm gauge SD.

0.005/0.025=20% SD ratio; squared ratio=4% variance contribution.

Teaching view 2 of 2

Explain two honest percentages from one measurement study

Completed record combines .003 and .004 mm SD components into .005 mm and distinguishes 20% of total SD from 4% of total variance.
Original OPEX teaching diagram. Follow the steps below, then try the practice question. View full size ↗

Fictional case: a gauge study uses ten representative parts, three operators and two repeated measurements, giving 60 readings. The core exhibit supplies repeatability SD .003 mm, reproducibility SD .004 mm and total study SD .025 mm. Metrologist Eve must explain a report that labels gauge variation both 20% and 4%, without claiming these components were calculated from an unseen raw dataset.

Follow the method

  1. Gauge variance
  2. Gauge SD
  3. Share of total SD
  4. Share of total variance
  5. Fitness decision

Read the example carefully

Review and redesign the representative-artifact selection before interpreting the ratio as evidence for normal production decisions. Preserve the original study scope.

The denominator and apparent relative variation depend on the study population. A ratio from an artificially narrow range can be misleading for the intended use.

Apply the method

Twenty percent and four percent can both be correct

Distinguish measurement-study design from supplied variance estimates and explain why standard-deviation and variance percentages differ.

Fictional case: a gauge study uses ten representative parts, three operators and two repeated measurements, giving 60 readings. The core exhibit supplies repeatability SD .003 mm, reproducibility SD .004 mm and total study SD .025 mm. Metrologist Eve must explain a report that labels gauge variation both 20% and 4%, without claiming these components were calculated from an unseen raw dataset.

Role: Measurement-system specialist and inspection owner

Normal condition

The study represents intended parts, appraisers and conditions; repeats preserve identity and avoid memory effects; the analysis method and denominator are explicit.

The gap

A manager adds .003 and .004 to obtain .007 mm and treats the larger percentage as evidence that the smaller one is dishonest.

  • Components are supplied estimates for an arithmetic illustration.
  • No universal acceptance threshold or complete MSA conclusion is supplied.
Supplied case inputs
Study itemSupplied value
Design10 parts ×3 operators ×2 repeats =60 readings
Repeatability SD.003 mm
Reproducibility SD.004 mm
Total study SD.025 mm
Raw readings / fitted modelNot supplied in this calculation exercise
  1. Define the measurement decision

    Eve records the characteristic, range of intended parts, fixture, gauge and appraisers. She asks whether the study represents actual use rather than ten unusually similar parts selected for convenience.

    Why: A precise calculation cannot repair an unrepresentative study. Measurement fitness concerns the decisions the system must support.

    Evidence: The study plan identifies artifacts, operators, conditions and intended use.

  2. Protect repeated observations

    The illustrative plan has 60 measurement opportunities. Eve assigns stable part identities and a blinded/randomized order where suitable, with actual observations recorded rather than copied from earlier rounds.

    Why: Repeats are meant to reveal measurement variation, not recall of the previous reading. The design is an example, not a mandated sample size for every measurement system.

    Evidence: A measurement schedule distinguishes part, operator and repeat.

  3. Combine supplied variance components

    She squares the SDs, adds .000009 and .000016mm², then takes the square root:.005 mm. She does not add standard deviations directly.

    Why: Independent component variances add under the stated model. Their square root returns the result to measurement units.

    Evidence: Combined gauge variance .000025mm² and SD .005 mm.

  4. Label the two denominators

    Gauge SD divided by total SD is .005/.025=.20 or 20%. Gauge variance divided by total variance is .000025/.000625=.04 or 4%.

    Why: The two percentages answer different questions and are mathematically consistent. A common study-variation multiplier cancels when applied to both numerator and denominator.

    Evidence: The report labels percent of total SD separately from percent of total variance.

  5. Interpret fitness with the missing context

    Eve requests the fitted-model details, representative data and applicable decision criteria. She also considers bias, resolution, stability and other measurement effects beyond repeatability/reproducibility.

    Why: A small variance ratio alone does not establish every aspect of measurement fitness. Calibration status and repeatability are related evidence, not interchangeable approvals.

    Evidence: The conclusion reports the supplied arithmetic and lists the remaining fitness evidence.

Completed measurement-component record
QuantityCalculationResult
Gauge variance.003² +.004².000025mm²
Gauge SD√.000025.005 mm
Share of total SD.005/.02520%
Share of total variance.005²/.025²4%
Fitness decisionApplicable requirements and complete studyNot established here

The selected parts cover almost no process range

The ten study parts were all chosen from one narrow group, unlike the range encountered in normal inspection.

Review and redesign the representative-artifact selection before interpreting the ratio as evidence for normal production decisions. Preserve the original study scope.

The denominator and apparent relative variation depend on the study population. A ratio from an artificially narrow range can be misleading for the intended use.

The revised plan explains how selected artifacts represent the measurement task.

Reconcile a changed set of components

New supplied estimates are repeatability SD .006 mm, reproducibility SD .008 mm and total SD .050 mm. A trainee reports combined SD .014 mm.

Changed practice inputs
ComponentSupplied SD
Repeatability.006 mm
Reproducibility.008 mm
Total.050 mm

Your task

  1. Calculate combined gauge SD using variances.
  2. Calculate the two labelled percentages.
  3. Identify one missing study-design and one missing fitness consideration.

Prepare your worksheet

  • Component squares
  • Combined variance and SD
  • Denominator labels
  • Design scope
  • Decision limitation
Reveal the answer and reasoning

Gauge variance=.000036+.000064=.000100mm², so SD=.010 mm. The SD share is .010/.050=20%; variance share is .0001/.0025=4%.

The .014 result incorrectly adds SDs. Representative parts/appraisers and a suitable analysis model still need evidence, as do relevant bias, resolution, stability or decision criteria.

Worked answer record
MetricResultUnit or denominator
Combined gauge SD.010mm
SD share20%Total SD
Variance share4%Total variance

Check these interpretations

  • Standard deviations do not add as independent variances do.
  • A supplied component calculation is not an executed measurement study.

Check your work

  • Calculate in squared units and return to mm.
  • Label both percentages.
  • Separate arithmetic from measurement approval.

Run a practice session

Materials

  • Measurement schedule
  • Component cards
  • Calculator
  1. Describe a repeat · 5 minutes

    How would memory of a reading bias the exercise?

  2. Combine components · 8 minutes

    Why square before adding?

  3. Work the changed estimates · 10 minutes

    How can 20% and 4% agree?

  4. Debrief fitness · 5 minutes

    What can this ratio not tell us?

Debrief

  • Ask learners to state the denominator aloud.
  • Challenge the idea that one example design is a universal minimum.

Draw a units column beside every intermediate calculation.

Transfer into the work

Owner: Measurement-system owner

Record: Study plan, raw readings, model, component labels and fitness decision

Review: Before use for a new decision and after material method changes

Evidence: Representative design and suitable measurement evidence

Improve the method or study design and reassess rather than changing percentage labels to appear acceptable.

Build on reliable methods

Sources and further reading

  • NIST: Gauge R&R ↗

    Measurement characterization covers repeatability, reproducibility, stability, bias, resolution, linearity and other error sources.

    Public primary-source summary; underlying paid standards/forms are not reproduced.
  • NIST: Gauge study design ↗

    A measurement study needs considered choices of artifacts, operators, gauges and measurement levels.

    Public primary-source summary; underlying paid standards/forms are not reproduced.
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