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Chart nonconforming units with the right denominator

Classify each inspected unit once as conforming or nonconforming.. Follow the visual, practise a decision, then check your thinking.

Fictional teaching examples and AI-generated illustrations. Proposed changes and goals are not achieved results. Use the written instructions and check local conditions before applying a method.

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Teaching view 1 of 2

Chart nonconforming units with the right denominator

Separate p and np charts distinguish fractions from fixed-size counts. The p-chart samples alternate n 100 and n 200, with limits narrowing from 0.01–0.19 to 0.03636–0.16364 around 0.10. The np chart keeps n 100 with centre 10 and limits 1–19 units. One unit contributes at most one nonconforming classification.
Original OPEX teaching diagram. Follow the steps below, then try the practice question. View full size ↗

For nonconforming units, every inspected unit contributes at most one failure to the count. A p chart displays the fraction nonconforming and can accommodate different sample sizes with different limits. An np chart displays the count and assumes a constant sample size in this basic form. A larger sample narrows the p-chart limits because it changes the expected sampling variation; it does not change the customer specification. Estimate the baseline from appropriate totals and retain each denominator. The example uses a supplied baseline proportion. Dependence, changing product mix and unsuitable binomial assumptions require investigation rather than blind application of these formulas.

Follow the method

  1. p: sample size may vary
  2. Fraction nonconforming
  3. Sample in time order
  4. Center: 0.1
  5. LCL: 0.01 / 0.0363604
  6. UCL: 0.19 / 0.16364
  7. np: fixed sample size 100
  8. Nonconforming units (count)
  9. Center: 10
  10. LCL: 1
  11. UCL: 19

Read the example carefully

pbar0.10; n100 limits0.01–0.19; n200 limits0.03636–0.16364.

Fixed n100 gives np centre10 and limits1–19.

Basic binomial limits; retain all sample sizes.

Teaching view 2 of 2

Match each unit fraction to its own sample-size limits

The completed record contrasts p-chart limits for 100 and 200 inspected units with a separate np count view at fixed n = 100. It distinguishes the two scales and states that the chart alone supplies no cause or acceptance verdict.
Original OPEX teaching diagram. Follow the steps below, then try the practice question. View full size ↗

Fictional case: an inspection desk classifies each item once as conforming or nonconforming. A supplied historical fraction is .10. The core p example uses sample sizes 100,200,100,200 and counts 8,24,11,17; the separate np example always inspects 100 and records 8,12,11,9. Analyst Pia explains why limits must reflect the observation design.

Follow the method

  1. p at n100
  2. p at n200
  3. np at fixed n100
  4. Interpretation

Read the example carefully

Retain 20/200=.10 and handle the sampling-design change through the chart owner; do not compare 20 directly with the old fixed-n100 upper limit 19.

The change in denominator alone can explain the count increase. The original chart was designed for fixed n.

Apply the method

Twice the count, the same fraction

Keep nonconforming-unit counts linked to sample size, calculate the appropriate fraction or fixed-size count limits, and interpret a changed denominator.

Fictional case: an inspection desk classifies each item once as conforming or nonconforming. A supplied historical fraction is .10. The core p example uses sample sizes 100,200,100,200 and counts 8,24,11,17; the separate np example always inspects 100 and records 8,12,11,9. Analyst Pia explains why limits must reflect the observation design.

Role: Quality analyst and inspection owner

Normal condition

Every sample records its actual inspected amount; one item contributes at most one nonconforming classification; model and baseline are suitable for the declared process.

The gap

A supervisor compares 24 failed items in 200 with 12 in 100 and declares the larger sample twice as bad. Both are 12%.

  • Historical pbar=.10 is supplied, not estimated from these four samples.
  • Dependence, overdispersion or changing risk can require another model; these are not acceptance-sampling limits.
Supplied case inputs
SampleInspected / nonconformingFraction
1100 /8.08
2200 /24.12
3100 /11.11
4200 /17.085
  1. Confirm what is counted

    Pia checks that an item with several faults is still classified once in this unit-count record. She retains fault-category details separately if needed.

    Why: A p or np chart describes affected units, not the number of faults within them. Mixing those numerators would break the interpretation.

    Evidence: Each count is bounded by its inspected sample size.

  2. Calculate fractions and preserve n

    She divides each sample count by its actual n and retains n beside the plotted point. Sample 2 is 24/200=.12, not 24/100.

    Why: Different sample sizes can produce different counts with the same fraction. The denominator also determines the expected sampling variation.

    Evidence: The sequence is .08,.12,.11,.085 with its four actual sample sizes.

  3. Apply the supplied p baseline

    Using .10 ±3√(.10×.90/n), n100 gives .01–.19; n200 gives approximately .03636–.16364. The center stays .10.

    Why: The larger sample has narrower fraction limits under this model. Reusing fixed limits for all denominators would discard relevant information.

    Evidence: Each point receives limits matching its own n; limits remain within possible fraction values.

  4. Explain the fixed-size count view

    For the separate fixed-n100 illustration, np center is 10 and limits are 1–19 nonconforming units. Pia labels counts and does not mix this axis with fractions.

    Why: A count view is interpretable when the inspected amount is fixed. A p view can also be used with fixed n if it is clearly labelled.

    Evidence: The np sequence 8,12,11,9 uses n100 throughout.

  5. Record a response rather than a verdict

    Pia documents any signal against the supplied baseline and checks measurement, sampling and process context. Product containment and release follow the applicable quality procedure.

    Why: A point within statistical limits is not proof that the defect level is acceptable. A signal identifies changed behavior worth responding to, not its cause.

    Evidence: The record separates chart evidence, product decisions and investigation ownership.

Completed denominator-to-limit record
DisplayBaseline / limitsMeaning
p at n100Center .10; .01–.19Fraction of inspected units
p at n200Center .10; .03636–.16364Narrower fraction limits
np at fixed n100Center 10;1–19Count of nonconforming units
InterpretationNo cause or acceptance verdictUse the declared response plan

Inspection amount changes on the np record

A busy shift inspects 200 instead of 100 and enters 20 in the count chart.

Retain 20/200=.10 and handle the sampling-design change through the chart owner; do not compare 20 directly with the old fixed-n100 upper limit 19.

The change in denominator alone can explain the count increase. The original chart was designed for fixed n.

The observation is preserved with n200 and a documented display/design decision.

A signal at the larger sample size

New observation under the supplied pbar=.10 baseline:36 nonconforming units among 200 inspected. A colleague proposes dividing by 100 because that was yesterday’s amount.

Changed practice inputs
GivenValue
Nonconforming36
Inspected200
Historical pbar.10

Your task

  1. Calculate the fraction and applicable limits.
  2. Identify whether the point exceeds the stated upper limit.
  3. Explain why this is neither 36% nor an automatic product-disposition instruction.

Prepare your worksheet

  • Actual n
  • Fraction
  • Sample-specific limits
  • Signal statement
  • Response and missing authority
Reveal the answer and reasoning

36/200=.18. For n200, the supplied-baseline limits are approximately .03636–.16364; .18 exceeds the upper limit.

Report an upward signal and follow the approved response. Dividing by 100 invents a denominator; the chart itself does not decide the disposition of particular units.

Worked answer record
CalculationResultDecision
36/200.1818% observed
Upper limit.16364.18 is above UCL
Product statusSeparate applicable criteriaNo automatic release or scrap

Check these interpretations

  • A point within limits can still represent an unacceptable defect level.
  • Multiple faults on one item do not create multiple affected units.

Check your work

  • Use n200 consistently.
  • Distinguish fraction and count scales.
  • Preserve signal and response authority.

Run a practice session

Materials

  • Sample-size/count cards
  • Calculator
  • Blank response record
  1. Define affected units · 5 minutes

    Can one item contribute three here?

  2. Compare n100 and n200 · 8 minutes

    Why do fraction limits narrow?

  3. Evaluate 36 of 200 · 10 minutes

    What denominator and limit apply?

  4. Debrief · 5 minutes

    Why does a chart not authorize product release?

Debrief

  • Ask learners to explain why 12/100 and 24/200 are equal.
  • Challenge the unsupported 36% calculation by tracing the inspected population.

Write n next to each numerator before choosing a plotting scale.

Transfer into the work

Owner: SPC and inspection owners

Record: Count, denominator, baseline and sample-specific response record

Review: At each sampling interval and whenever sampling changes

Evidence: One classification per unit, correct n and verified response

Resolve denominator/model changes before applying a fixed-n interpretation.

Build on reliable methods

Sources and further reading

  • NIST: Proportions charts ↗

    The binomial model underlies fraction-nonconforming charts; limits depend on the sample denominator.

    Public primary-source summary; underlying paid standards/forms are not reproduced.
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  • Each unit classified once
  • Known sample sizes and suitable binomial assumptions
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